Institution: SONALI BANK LTD Exam: Sonali Bank Ltd - Assistant Programmer - 26.08.2016 ||
Topic: Arithmetic Mathematics (পাটিগণিত), Subject: Mathematics (সাধারণ গণিত)

Best Answer Explained in Below-:

To solve the problem, we start with the ratio of marbles among the three boys, which is given as 19:5:3. Let's denote the number of marbles each boy has based on this ratio. We can let the number of marbles for the boys be represented as follows:

- Boy 1: 19x
- Boy 2: 5x
- Boy 3: 3x

Here, 'x' is a common factor that will help us scale the numbers according to the ratio. We know from the problem that the boy with the least number of marbles has 9 marbles. According to our representation, this corresponds to the boy who has 3x marbles.

Setting 3x equal to 9 (the number of marbles for the least boy), we can solve for x:

\[
3x = 9 \\
x = 3
\]

Now that we have x, we can calculate the number of marbles for each boy:

- Boy 1 (19x): \( 19 \times 3 = 57 \)
- Boy 2 (5x): \( 5 \times 3 = 15 \)
- Boy 3 (3x): \( 3 \times 3 = 9 \)

Now, we can clearly see that Boy 1 has the highest number of marbles, which equals 57. Therefore, the answer is A) 57, confirming that Boy 1 has significantly more marbles than the others, solidifying this option as the correct choice.