Institution: Bank Asia Ltd Exam: Bank Asia Ltd - Management Trainee Officer - 22.05.2015 ||
Topic: Arithmetic Mathematics (পাটিগণিত), Subject: Mathematics (সাধারণ গণিত)

Best Answer Explained in Below-:

To find the possible maximum wage among the workers, we first need to analyze the provided information. The average daily wage for 10 workers is Tk. 400, which means the total wages for all workers combined can be calculated as follows:

\[
\text{Total wages} = \text{Average wage} \times \text{Number of workers} = 400 \times 10 = Tk. 4000
\]

Now, we also know that the lowest wage among these workers is Tk. 300. If we assume one worker earns Tk. 300, we can express the total wages of the remaining 9 workers. Let’s denote the total wage of the remaining 9 workers as \( x \):

\[
x + 300 = 4000
\]

Solving for \( x \):

\[
x = 4000 - 300 = 3700
\]

The average wage of the other 9 workers must be maximized to find the maximum possible wage of one individual. Since we want to maximize the wage of one worker, we assume that the other 8 workers earn the minimum possible, which would ideally be Tk. 300 each. Therefore, their total wages would be:

\[
\text{Wages of 8 workers} = 300 \times 8 = 2400
\]

Now, we can calculate the wage of the 9th worker as follows:

\[
\text{Wage of the 9th worker} = 3700 - 2400 = 1300
\]

Thus, when considering that one worker earns the lowest wage of Tk. 300, the maximum possible wage that the remaining worker can have is Tk. 1300. Therefore, the correct answer is option A) 1300.