x2+y2+6x-4y-12=0 বৃত্তের কেন্দ্র ও ব্যাসার্ধ কত?

x2+y2+6x-4y-12=0 বৃত্তের কেন্দ্র ও ব্যাসার্ধ কত?

\(x^{2}\)+\(y^{2}\)+6x-4y-12=0 বৃত্তের কেন্দ্র ও ব্যাসার্ধ কত? ?

Created: 1 week ago | Updated: 1 week ago | Created By:

Imran Ahmed

(−3, 2), 5

(−6, 4), 4

(3, −2), 5

(−3, −2), 5

0 1

No comments yet.

Think of a number and then double the number Add 6 and multiply the result by 10. Now divide the result by 20 , then subtract the number you first thought out. What is the result?

B can work thrice as much as A can do in a day. If they together can do 4/15 parts of a work in 10 days, in how many days will B finish the work alone?

Related Question

What do you call a group of sheep?

89

For which historical event the year of 1789 is renowned?

36

যদি x2 +px + 4=0 এর মূল দুইটি সমান হয় এবং p>0 হয়, তবে p এর মান কত?

35

ADMINISTRATION শব্দটি দ্বারা নিচের কোন শব্দটি গঠন করা যায় না?

28

What was the name of the first cloned sheep?

22

State whether the given statement is true or false. !DOCTYPE is case sensitive”.

22

The ancient Indian scholar statesman , Kautilya belonged to which dynasty?

20

Who directed the film named 'Palassy to 32, Dhanmondi ' ?

18

If the figure below , what is the slepe of line?

17

In what year did Shakespeare died?

17

Advertishment

Need Custom Questions or Projects?

Email us at call@nezef.com for custom questions or project quotes.

Social Links

Quick Links

Stay Connected

© 2024 Nezef. All rights reserved.