Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, t

Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ? ?

Created: 1 week ago | Updated: 1 week ago | Created By:

Imran Ahmed

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Best Answer Explained in Below-:

(A + B) ' 2 hours work when open d = 1/6 + 1/4 = 5/12 (A + B) 4 hours work when open = 5/12 × 2 = 5/6 Remaining work 1 - 5/6 = 1/6 Now, its A turn in 5th hour 1/6 work will be done by A in 1 hour Total time = 4 + 1 = 5 hours

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Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ? ?

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