Three consecutive eveb numbers are such that if the first is divided by 6, the second by 4 and the third by 7, the sum of the quotients is 38. Find the numbers.

Three consecutive eveb numbers are such that if the first is divided by 6, the second by 4 and the third by 7, the sum of the quotients is 38. Find the numbers. ?

Created: 1 week ago | Updated: 1 week ago | Created By:

Imran Ahmed

22, 24, 26

32, 34, 36

46,48,50

66,68, 70

0 1

Best Answer Explained in Below-:

এটি দুটি উপায় করা যায়, একটি উপায়, \(a^{6}\) + a + 24 + a + 47 = 38 ; এটি solve করতে হবে। যেখানে three consecutive even number হচ্ছে a,a + 2,a + 4 অথবা Answer এ দেয়া option গুলো বসিয়ে যোগফল 38 আসে নাকি check করা। এখন (d) তে, 666 + 684 + 707 = 38

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