Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?

Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X? ?

Created: 1 week ago | Updated: 1 week ago | Created By:

Imran Ahmed

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Best Answer Explained in Below-:

ধরি, প্রথম number টি a তাহলে, a + a + 1 + a + 2 + a + 3 + a + 4 = 265 বা, 5a + 10 = 265 বা, a = 265 - 105 = 51 এখন বাকি 5 টি number এর average = 15 (a + 5 + a + 6 + a + 7 + a + 8 + a + 9) = 15(51 × 5 + 35) = (51 + 7) = 58

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Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X? ?

Together, Andrea and Brian weight p pounds. Brian weight 10 pounds more than Andrea. Brain and Andrea's dog Cubby, weight p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

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