b.Eighteen years ago, a father was three times as old as his son. Now, the father is only twice as old as his son. then, the sum of the present ages of the son

b.Eighteen years ago, a father was three times as old as his son. Now, the father is only twice as old as his son. then, the sum of the present ages of the son and the father is:

b.Eighteen years ago, a father was three times as old as his son. Now, the father is only twice as old as his son. then, the sum of the present ages of the son and the father is: ?

Created: 2 days ago | Updated: 2 days ago | Created By:

Imran Ahmed

105

108

0 1

Best Answer Explained in Below-:

Let the present age of father be x and that of his Son Be yThen 18 years ago Father's age =x−18 Son's age =y−18But given that x−18=3(y−18) ⇒x−18=3y−54 ⇒x−3y+36=0 (1)Also given that x=2y (2)From (1) & (2) x−3y=36=0⇒2y−3y+36=0⇒y=36Putting y=36 in (2)x=2y=2×36=72Sum of their present ages =x+\(y^{72}\)+36=108

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b.Eighteen years ago, a father was three times as old as his son. Now, the father is only twice as old as his son. then, the sum of the present ages of the son and the father is: ?

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