A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ?

A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ?

A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ? ?

Created: 1 week ago | Updated: 1 week ago | Created By:

Imran Ahmed

10/21

11/21

2/7

5/7

0 1

Best Answer Explained in Below-:

n(S) = 7C2 = 21 n( E) = 5C2 = 5! /2! 3! = 10 কোনো বলই নীল না হওয়ার সম্ভাবনা = n( E) / n(S) = 10/21

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